Código de Python - recursividad con Python

# To run this, you can install BeautifulSoup

# https://pypi.python.org/pypi/beautifulsoup4

import re

import urllib

from bs4 import BeautifulSoup

import ssl

var = ""

def recorrer1(link,counta,contados):

    html = urllib.urlopen(link).read()

    soup = BeautifulSoup(html, "html.parser")

    tags = soup('a')

    c1 = 1

    c2 = 1

    for tag in tags:

        if c1 == counta:

           #print(tag.get('href', None))

            html2 = urllib.urlopen(tag.get('href', None)).read()

            soup2 = BeautifulSoup(html2, "html.parser")

            return tag.get('href', None)

        c1 = c1 + 1

# Ignore SSL certificate errors

ctx = ssl.create_default_context()

ctx.check_hostname = False

ctx.verify_mode = ssl.CERT_NONE

url = raw_input('Enter URL: ')

cont2 = int(raw_input('Enter count: '))

cont1 = int(raw_input('Enter position: '))

count3 = 1

# Retrieve all of the anchor tags

#url = 'http://py4e-data.dr-chuck.net/known_by_Fikret.html'

print "Retrieving: ",url

var = recorrer1(url,cont1,cont2)

print "Retrieving: ",var

while count3 < cont2 :

   print "Retrieving: ", recorrer1(var,cont1,cont2)

   var = recorrer1(var,cont1,cont2)

   count3 = count3 + 1