Dev - C++ - Dados los valores X y N, obtener el valor de E mediante la suma de la serie

#include <iostream>

#include <cmath>

using namespace std;

long int factorial(long int n);

int main()

{

    int x, n;

    float e;

    cout << "\nX: "; cin >> x;

    cout << "N: "; cin >> n;

    e = 1 + x;

    for (int i = n; i >= 2; i--)

    {

        e += float(pow(x, i)) / factorial(i);

    }

    cout << "\nResultado: " << e << endl;

    return 0;

}

long int factorial(long int n)

{

    if (n <= 1)

        return 1;

    else

        return n * factorial(n - 1);

}

#include <iostream>

using namespace std;

int main()

{

    int x, n;

    cout << "\nX: "; cin >> x;

    cout << "N: "; cin >> n;

    float e = 1;

    float t = 1;

    for (int i = 1; i <= n; i++)

    {

        t = float(t * x) / i;

        e += t;

    }

    cout << "\nResultado: " << e << endl;

    return 0;

}