Dev - C++ - Escriba una función que acepte un arreglo de enteros en c++

#include <iostream>

using namespace std;

int modaArreglo(int v[], int n);

int main()

{

    int moda;

    int v[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 6};

    moda = modaArreglo(v, 10);

    if (moda != -1)

        cout << "\nModa: " << moda << endl;

    else

        cout << "\nSin Moda" << endl;

    return 0;

}

int modaArreglo(int v[], int n)

{

    int moda, count = 0;

    for (int i = 0; i < n; i++)

    {

        int temp = 0;

        for (int j = 0; j < n; j++)

        {

            if (v[i] == v[j])

                temp++;

        }

        if (temp > count)

        {

            count = temp;

            moda = v[i];

        }

     }

     return moda = count == 1 ? -1 : moda;

}