Dev - C++ - Colocar el arreglo A de forma inversa al arreglo b

#include <iostream>

#include <vector>

using namespace std;

int main()

{

	vector<int> g1;

    vector<int> g2;

	for (int i = 0; i < 5; i++)

		g1.push_back(i);

    //arreglo A

    cout << "Arreglo A: ";

    for (auto e : g1)

        cout << e << " ";

	cout << "\nArreglo B inverso de A: ";

	for (auto ir = g1.rbegin(); ir != g1.rend(); ++ir) {

        g2.push_back(*ir);

		cout << *ir << " ";

    }

    cout << endl;

	return 0;

}