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Crear cuentaCrear cuenta| Pregunta: | 66971 - CONTROLADOR DERIVATIVO |
| Autor: | Alejandro Martinez |
| % programa 5.4, Luyben, pag. 123. (eqm) 18 nov 98. % "three isothermal cstr (closedloop)" %------------------------------------------------------ % (with proportional feedback controller) % disturbance (cad) is a step change at time equal zero % from 0 to 0.2 % time is in minutes clear format short e % initial conditions time=0; ca1=0.4; ca2=0.2; xx=[]; ca3=0.1; ca3set=0.1; erint=0; % disturbance cad=0.2; % parameter values tau=2; k=0.5; kc=30; taui=5; delta=0.01; tprint=0; while(time<=30) % feedback controller e=ca3set-ca3; cam=0.8+kc*(e+erint/taui); cao=cam+cad; % evaluate derivatives ca1dot=(cao-ca1)/tau-k*ca1; ca2dot=(ca1-ca2)/tau-k*ca2; ca3dot=(ca2-ca3)/tau-k*ca3; if(time>=tprint) xx=[xx;time,ca1,ca2,ca3,cam]; tprint=tprint+0.1; end ca1=ca1+ca1dot*delta; ca2=ca2+ca2dot*delta; ca3=ca3+ca3dot*delta; erint=erint+e*delta; time=time+delta; end xx subplot(2,1,1),plot(xx(:,1),xx(:,5)),ylabel('Cam'),grid subplot(2,1,2),plot(xx(:,1),xx(:,4)),ylabel('Ca3'),grid xlabel('Time, min') En este programa solo se utiliza la parte PI, ¿como se implementaria la parte derivativa? | |