Matlab - Sumatorio

sum=0;

for n=1:3

sum=sum+1/(2^n);

end

Iteración 1:

sum=0;

n=1;    sum=sum+1/2^n=0+1/2^1=1/2

Iteración 2:

sum=1/2;

n=2;    sum=sum+1/2^n=1/2+1/2^2=1/2+1/4=3/4

Iteración 3:

sum=3/4;

n=3;    sum=sum+1/2^n=3/4+1/2^3=3/4+1/8=7/8

por lo tanto sum=7/8

forma analítica sum=1/2+1/4+1/8=7/8

for n=1:5

f(n)=1/n;

s=sum(f);

end

s

>> n=1:50

s=sum(1./2.^n)

n =

  Columns 1 through 22

     1     2     3     4     5     6     7     8     9    10    11    12    13    14    15    16    17    18    19    20    21    22

  Columns 23 through 44

    23    24    25    26    27    28    29    30    31    32    33    34    35    36    37    38    39    40    41    42    43    44

  Columns 45 through 50

    45    46    47    48    49    50

s=

    1.0000