JavaScript - Algoritmo averiguar un número

def f(num):

    x, y = 0, 1

    while num > 0:

        x += (num % 10)

        y *= (num % 10)

        num //= 10

    return x == y

>>> f(123) # True

>>> f(5122) # True

>>> f(1244) # False

const sumNumbers = n => n.toString().split('').reduce((acum, el) => acum + +el, 0);

const multNumbers = n => n.toString().split('').reduce((acum, el) => acum * +el, 1);

for (let i=11111; i<99999; i++) {

    if (sumNumbers(i)==multNumbers(i)) {

        console.log(i);

    }

}

11125

11133

11152

11215

11222

11251

11313

11331

11512

11521

12115

12122

12151

12212

12221

12511

13113

13131

13311

15112

15121

15211

21115

21122

21151

21212

21221

21511

22112

22121

22211

25111

31113

31131

31311

33111

51112

51121

51211

52111

<script>

const sumNumbers = n => n.toString().split('').reduce((acum, el) => acum + +el, 0);

const multNumbers = n => n.toString().split('').reduce((acum, el) => acum * +el, 1);

const increment = n => n.toString().split('').every((el, index, array) => index>0 ? +el >= array[index-1] : true);

for (let i=11111; i<99999; i++) {

    if (sumNumbers(i)==multNumbers(i) && increment(i)) {

        document.write("<br>"+i);

    }

}

</script>

11125

11133

11222