Java - Metodo jacobi podrian ayudarme pasarlo en el lenguaje Java, esta en lenguaje python

public class Jacobi {

  private static double f1(double y, double z) {

    return (1 + y + z) / 3;

  }

  private static double f2(double x, double z) {

    return (3 + x - z) / 3;

  }

  private static double f3(double x, double y) {

    return (7 - 2 * x - y) / 4;

  }

  public static void main(String[] args) {

    double x0 = 0, x1 = 0;

    double y0 = 0, y1 = 0;

    double z0 = 0, z1 = 0;

    int count = 1;

    try {

      // Leemos la tolerancia del error

      System.out.print("Introduzca la tolerancia del error: ");

      float e = Float.parseFloat(System.console().readLine().trim());

      boolean condition = true;

      // Implementacion del metodo Jacobi

      System.out.println("\n-\tx\ty\tz\n");

      System.out.println(count + "\t" + x0 + "\t" + y0 + "\t" + z0 + "\n");

      while (condition) {

        x1 = f1(y0, z0);

        y1 = f2(x0, z0);

        z1 = f3(x0, y0);

        System.out.println(count + "\t" + x1 + "\t" + y1 + "\t" + z1 + "\n");

        double e1 = Math.abs(x0 - x1);

        double e2 = Math.abs(y0 - y1);

        double e3 = Math.abs(z0 - z1);

        count++;

        x0 = x1;

        y0 = y1;

        z0 = z1;

        condition = (e1 > e) && (e2 > e) && (e3 > e);

      }

      System.out.println("\nSolución: x = " + x1 + ", y = " + y1 + ", z = " + z1 + "\n");

    } catch (NumberFormatException e) {

      System.err.println("ERROR: La entrada no es un numero decimal: " + e.getMessage());

    }

  }

}